[sdiy] JFET switch question

[JH.]

>If I understand what you are asking -- I believe the G potential is
>indeterminate if it is only connected to a reverse biased diode. Just
>floating at a very high impedance.  A large value resistor to the channel
>is basically a short circuit.  This ensures that the device is on the Vgs =
>0 curve of the Id vs Vds characteristics, where you have the lowest channel
>resistance and the best channel linearity.

Hi Ian,

yes, I think I understand that.
Theoretically, the G potential is indeterminate, except for leakage of the 
G-DS diode.
But that's also true for the circuit version with a 100nF cap from G to GND 
(without a resistor),
so DC-wise there should not be a difference if I just omit the 100nF.

I guess I'll add the resistors just to be sure. But it's a curcuit with 
about 30 such switches ...


JH. (working on the new combined Hammond Scanner Vibrato and generic 
Interpolating Scanner PCB.)