[sdiy] Buchla 194 Fixed Bandpass Filter analysis
Aaron Lanterman
lanterma at ece.gatech.edu
Thu Apr 17 04:50:23 CEST 2008
To get some practice analyzing circuits with transistors, I started
looking at the Buchla 194 Fixed Bandpass Filter, as redrawn by Marjan
Urekar:
http://members.tripod.com/urekarm/synth/buchla_bpf.pdf
The filters are all Sallen-Keys.
Numbering them from top down, the 1st filter is a 2nd order highpass,
the next two are 2nd order lowpass followed by 2nd order highpass, and
the 4th one is a 2nd order low-pass.
There are three emitter followers in the circuit; one as a buffer
right at the beginning, and another two as part of lowpass filters in
the 2nd and 3rd filter (from the top). The 1st and 4th filters, and
the second filter section of the 2nd and 3rd, have two transistors
forming a buffer in the "Sziklai" configuration, according to my
trusty Horowitz and Hill.
The circuit runs off a single supply, so the transistors are biased at
around 6 volts via 68K and 100K resistors. That's a little less than
7.5, which would be halfway between the rails. A biasing network
appears at the initial emitter follower, and also in the highpass
filters (since they appear after a cap which would block the DC bias).
Questions:
1) The highpass S-K has a "feedback resistor" and a "resistor to
ground." When I'm considering the "resistor to ground," should I think
of the 68K and 100K biasing setup as both being resistors in parallel
to "AC ground?" If so, my "to ground" resistor is actually 68K || 100K
= 40K. (It's kind of embarassing to ask this, being an ECE prof, but
it's been a long time since I actually dug into a transistor circuit -
probably when I took the sophomore electronics class, uh, 17 years ago).
With this figured out, I can compute the cutoffs and Qs of the various
filters.
2) All of the bases of the voltage buffers, except for the first one,
have 10K resistors going into the bases. Why are those 10K resistors
there?
3) There's a 2K2 and 100K voltage divider right at the beginning that
attenuates the signal by a factor of 50, presumably to get the signal
into the "linear small signal analysis" range. But... I don't see
anywhere where the gain is brought back up at the end! Is there
something I'm missing?
I thank the list, as always, for its collective wisdom!
I'm thinking it would be fun to create a modern version of this that
just uses op amps and a split supply.
- Aaron
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