[sdiy] How to discharge a capacitor ?

harrybissell harrybissell at prodigy.net
Wed Nov 16 22:20:58 CET 2005


uhhh....

"my calculator is dyslexic ???"   :^P

H^) harry

Ingo Debus wrote:

> Am 16.11.2005 um 03:21 schrieb harrybissell:
>
> > 50V / 1Kohms = .05A (peak)
> > .05A x 50V = 25W (peak)
> >
>
> Huh? Wouldn't that be:
> .05A x 50V = 2.5W  ?
>
> Ingo




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