[sdiy] How to discharge a capacitor ?

Ingo Debus debus at cityweb.de
Wed Nov 16 20:02:06 CET 2005

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Am 16.11.2005 um 03:21 schrieb harrybissell:

> 50V / 1Kohms = .05A (peak)
> .05A x 50V = 25W (peak)
>

Huh? Wouldn't that be:
.05A x 50V = 2.5W  ?

Ingo

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