[sdiy] Diode voltage drop
Fredrik Carlqvist
Fredrik.Carlqvist at iar.se
Mon Aug 1 11:37:13 CEST 2005
I suppose Q5 and Q6 are power transistors like 2N3055?
Probably D2 and D3 are used directly as a voltage source for biasing the
output transistors.
I think you'll be ok with 1N400x. The difference in forward voltage at
currents between 100 and 200 mA is not so big. Since 1N400x will have a
lower drop than the specified diode, there should not be a risk of
thermal feedback.
However, crossover distorsion at lower currents could be slightly
bigger. But since they are not mounted on the power trannies (it seems),
I don't think they are critical.
Without the values of resistors, transistor types and voltages, it is
hard to say exactly what is going to happen. I guess you'll just have to
try it. Or fry it? :-)
Fredrik C
> -----Original Message-----
> From: owner-synth-diy at dropmix.xs4all.nl
> [mailto:owner-synth-diy at dropmix.xs4all.nl] On Behalf Of Tom Arnold
> Sent: den 27 juli 2005 10:36
> To: synth-diy at dropmix.xs4all.nl
> Subject: [sdiy] Diode voltage drop
>
> So, I'm trying to identify a diode to replace it.
>
> First off, the schematic :
> http://home.insightbb.com/~dunn.greg/ST120/schem2.jpg
>
> Between Q3 and Q4 you'll see D2/D3 in series. They are specified
> as .8 volt drop at 140ma. In another schematic, the same
> part number is
> specified at .8 volt drop at 100ma.
>
> I'm wondering if I can get away with with a 1N400x, which has
> .8volt drop at
> more like 200ma. I could just leave these diodes in, but
> they'd be the only
> silicon I left stock in the whole unit, not that that is a
> bad thing.
>
> I just dont grok single ended amps, it'd help if I could
> locate my service
> manual which has a detailed circuit description in it...
>
> --
> -----------------------------------------------------------------
> - Tom Arnold - Free Synth DIY webspace http://www.sdiy.org
> - SynthGeek -
> - BBD Fanatic - "...is it a virus, a drug, or a religion?"
> - echo evho wjxo - Juanita Shrugs. "What's the difference?"
> --------------------
>
>
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