[sdiy] op amp integrators
Scott Gravenhorst
music.maker at gte.net
Wed Oct 13 17:19:29 CEST 2004
A resistor, pot or other current contol device would be placed at the
inverting input of the integrator. In a simple integrator circuit, this
controls how fast the capacitor charges.
"Thom Ash" <thom.ash at ntlworld.com> wrote:
>hi everyone.
>
>you might remember a while ago i posted about a module i made that
>generates a Lorenz attractor [www.aovt59.dsl.pipex.com/chaos.html for
>more info/mp3s]. anyway i've been thinking it would be cool to add a
>speed control to it and... well, i need some help :/
>
>the speed of the circuit is determined by the size of the three caps;
>each of these works with an op-amp to form a integrator like this
>['scuse the ascii]...
>
>
> +----||---+
> | |
> | |\ |
>dx | G-|+\___|__ x
>dt ---+---|-/
> |/
>
>
>i've been told that for a tuned circuit, the time constant is determined
>by a capacitor and a resistor... where would i put a pot to alter the
>speed?
>
>also, the fact that there are three seperate integrations that would
>ideally be controlled by one pot is confusing [to me anyway...] would
>this basically require it to be voltage-controlled and have the pot just
>generate a cv? if so, could someone point me in the right direction?
>
>thanks!
>
>thom
>
>
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