[sdiy] This circuit actually works?
Glen
mclilith at charter.net
Thu May 15 06:02:25 CEST 2003
I'm designing a pre-amp to use with my computer's sound card and a dynamic
microphone. I breadboarded a small test circuit tonight, and I really
didn't expect it to work, but it does. You can find the slightly simplified
schematic at this URL:
http://webpages.charter.net/glenweb/diy/pre01.gif
In the schematic, the op-amp power connections and compensation cap are
omitted. What I'm really interested in showing is the fact that there is
not the typical input resistor connected to the op-amp's inverting input.
I didn't expect the circuit to work like this, but it does!
I should mention that the microphone is a low impedance dynamic type. The
shield has been tied to one of the signal lines coming from the microphone
and connected to ground. I know this isn't a "proper" balanced input
circuit, but it does work. I also realize that the output is DC coupled,
and there is indeed a tiny amount of DC offset present, but my computer's
sound card doesn't seem to mind at all. (I might experiment next with
nulling out the offset, but I want to try and avoid a coupling cap for this
pre-amp.) I also realize the output signal is inverted, but it doesn't
matter for my purposes.
Without an input resistor, how do I calculate (not measure) the gain of
this pre-amp?
I realize that I have taken many shortcuts here, but what problems would
there be with not using a resistor between the mic and the inverting input
of the op-amp?
How do I calculate (not measure) the gain of this pre-amp?
What input impedance does the microphone see?
I'm interested in your comments.
thanks,
Glen
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