[sdiy] Continously Variable Symmetry Triangle

[ASSI]

On Monday 07 July 2003 23:51, ASSI wrote:
> (4) z(x) = 2 arcosh 1/sqrt(1-x^2)

With some more thinking I find that 

(5) z(x) = ln(1-x) - ln(1+x)

gives complete linearization of symmetry with respect to the modulation 
variable and is much easier implemented. Relax, it doesn't follow 
directly from (4)... :-) The interesting part is that you can use 
gain/attenuation on z(x) and get steeper (gain) or slower (attenuation) 
modulation with the (normalized) CV. Gain/attenuation on the individual 
subexpressions should also prove interesting, as this can make the 
modulation asymmetrically nonlinear with the CV. I'm not certain if I 
get around to write everything up over the weekend, but it should be 
enough at least for a preview.


Achim.
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