[sdiy] Linear Current Source Math Question
music.maker at gte.net
Sat Feb 22 19:32:03 CET 2003
I've been reading in chapter 4 of "The Art of Electronics"
about linear current sources that use a bipolar transistor
(b-e junction) in the feedback loop of an op-amp. It states
that the emitter current is (Vcc-Vin)/R and that Iout is the
same as Ie. Is it really that simple that one needs only
calculate the current in the feedback loop and that current
will be the output current (Ic)?
- A smoking gun is one that's already been fired.
- That which gets rewarded, gets done.
- What good are laws that only lawyers understand?
- Government: The other religion.
- The media's credibility should always be questioned.
-- Scott Gravenhorst | LegoManiac / Lego Trains / RIS 1.5
-- Linux Rex | RedWebMail by RedStarWare
-- FatMan: home1.GTE.NET/res0658s/FatMan/
-- NonFatMan: home1.GTE.NET/res0658s/electronics/
More information about the Synth-diy