[sdiy] RING MOD

[Don Tillman]

   > From: "Paul Maddox" <Paul.Maddox at Wavesynth.com>
   > Date: Thu, 18 Apr 2002 19:46:49 +0100
   > 
   > Ring Modulation = 4 quadrant multiplication , yes?

Yes!

   > if so, bascially in the time domain this comes down to;-
   > 
   > Z = X * Y
   > 
   > where X and Y are inputs, Z is result.
   > 
   > am I correct?

Yes, exactly.

Some implementations include attenuation for practical concerns in
cases like where you have two 10.0 Vp-p waveforms on the inputs and
you really don't want a 100 Vp-p waveform on the output.  So that
might be:

  Z = 0.1 * X * Y


  -- Don

-- 
Don Tillman
Palo Alto, California, USA
don at till.com
http://www.till.com