[sdiy] adding multiple LEDs to a simple circuit

[J. Larry Hendry]

Jeff, I am far from an expert on the subject (real newbie actually).
However, I cannot imagine taking jack outputs directly off of the 4526 pins
without buffering the output.  I like to use op amps for that.  However, if
you can tolerate a 0 to V+ rail size square you could use a 4050 hex buffer.
John Blacet used that approach in his Frequency Divider module to buffer his
divider output.   Regardless of your buffering plans, you can certainly use
the 4050 hex buffer to drive up to 6 LEDs as you had originally asked.  If
you have positive going outputs, connect them to the buffer inputs.  Connect
the hex output pins to the LED anode through a resistor and then connect the
cathode to ground.  The resistor size would determine the LED brightness.
With a 15 VDC 3.3k seems to be about right.  That gives you a one chip, 6
resistor solution to driving your LEDs.

BTW, Thanks to John Blacet for the learning experience of building his
frequency divider.  While I would have done things a little different (ain't
DIY great), I certainly learned a lot from this module.

Larry Hendry


----- Original Message -----
From: jeff bravine <jre-vin at apexmail.com>
To: <synth-diy at node12b53.a2000.nl>
Sent: Friday, May 25, 2001 1:50 AM
Subject: [sdiy] adding multiple LEDs to a simple circuit


hi everyone,

for a circuit consisting entirely of a CD4526 CMOS divide by n counter with
jacks wired to the IC's appropriate pins, what would be the most efficient
way to add LED indicators for input pins 2,5,6,14,&11?  I'm using a bipolar
12V supply.

Many Thanks!

jeff






























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