MIDI-guitar (was: Touch Switches/TS instruments )

[matti at devo.com]

Matrix scan? What about just a bunch of resistors in series, the end of each of 
which  is soldered onto a fret (in the neck, probably hollow). That aside, won't 
it's only being able to see that lowest note on each string make a problem? What 
about the resistor/capacitor actions of the fingers?

Quoting Theo <t.hogers at home.nl>:

> Have to see how this works:
> Give every fret its own voltage, do a matrix scann on the string and
> frets.
> No reson to cut up the frets, since you can see what is the "lowest"
> fret
> touched by the string.
> 
> Just an idea,
> Cheers Theo "can only play a Amaj"
> 
> ----- Original Message -----
> From: Paul Perry <pfperry at melbpc.org.au>
> To: Harry Bissell <harrybissell at prodigy.net>
> Cc: <synth-diy at node12b53.a2000.nl>
> Sent: Sunday, May 14, 2000 8:15 AM
> Subject: Re: MIDI-guitar (was: Touch Switches/TS instruments )
> 
> 
> > At 08:59 PM 14/05/00 -0400, Harry Bissell wrote:
> > >Reply:   no!
> > >The string is shorted to the fret before AND behind the finger... so
> if
> you
> > >have>fretted strings on any adjacent frets they are shorted together
> > through the
> > >X (strings) Y (frets) matrix. You CANNOT isolate the strings once
> they
> > >touch>the frets...
> > >that's why everyone cuts the frets into pieces...
> >
> > Yeah, but, since the two frets are adjacent, you just need a bit of
> logic
> to
> > say,
> > 'hey the 3rd string touches fret n and n+1, that means n'
> >
> > Now, you're going to come up with a counter example where there are
> more
> > than one
> > touching the same fret.. but, given that there are only 6 strings &
> they
> are
> > only
> > being fretted at a maximum of two adjacent points..
> > >
> > >Moral: everything easy has been done already !!!
> >
> > CounterMoral: think harder already !!!
> >
> > paul 'smartarse' perry melbourne australia
> >
>