FFT

[Christian Hofmann]

On Fri, 22 Oct 1999 00:12:24 +0200
Rene Schmitz <uzs159 at uni-bonn.de> wrote:

> But FFT is a transformation which obeys FFT(x+y) = FFT(x)+FFT(y)
> and also linear FFT(c*x)=c*FFT(x). Where x,y element of C^n, c = const.
> This would mean that all you'd get is a expensive way of mixing. Not
> morphing. To morph two spectra one would have to interpolate along the
> frequency axis. I.e. move a high frequency peak to a low frequency peak. To
> do this one would have to recognize the peaks and define a way in which
> they should move.

And even if you succeed in doing that - I doubt you'll get what you may
expect.
Assuming two signals with straight harmonics (i.e. integer multiples of
the base freq), maybe some peaks missing due to different filtering. 
These will sound more or less clean.
Now you start to shift those peaks around, and bingo - I'd bet you have
the nicest ring mod etc. sounds, because the harmonics need to go through
non-integer ratios.
Might be interesting, but probably not the kind of morphing you'd expect
between two "normal" sounds.

cu
Christian