mix resistor values...
List, Christopher
Chris.List at sc.siemens.com
Wed Aug 11 16:24:28 CEST 1999
I didn't have the log response on mine! I used 100K pots and 1M resistors
for all rows.
I'm just saying you *might* want it that way on just one row, for the added
variety. If, for example, you were planning on using a row to control master
volume and you had a linear CV for your VCA. Or perhaps you have a VC-ADSR
with linear CV inputs.
For pitch CV's, you would do best to stick with linear response. So you
might do best to just forget I ever mentioned anything about the log curve
:) Or use an external exp. amp if you want that...
One other thing that I did with my sequencer that I forgot to mention was
that for each row I have a switch that changes the scale for the row from 0v
-> 5v to
-5v -> +5v. I find this very helpful. I was able to do it with DPDT
switches, and without a lot of wires going from the switch to the op-amp on
the PCB, though I forget exactly what tricks I used to accomplish this. Note
that the input for each row is +15v when the row is "on" in all cases - the
switches are tied in to the summer on the output.
- CList
> -----Original Message-----
> From: WeAreAs1 at aol.com [SMTP:WeAreAs1 at aol.com]
> Sent: Wednesday, August 11, 1999 10:04 AM
> To: Chris.List at sc.siemens.com; synth-diy at mailhost.bpa.nl
> Subject: Re: RE: mix resistor values...
>
>
> In a message dated 8/11/99 5:05:54 AM, you wrote:
>
> <<You might want one row of pots with
> the pseudo-log curve you get from a low pot + high resistor combination...
>
> For my seq. I used 100K pots with 1Meg resistors. I never had (or noticed)
> a
> problem with noise - but then I have no facility for muxing in external
> audio to one of the rows, I only using it for generating CV's. >>
>
> Hello Chris -
>
> Why did you want the pseudo-log curve on your CV pots? I would think that
>
> linear pot response would be best for tuning pitches (when driving
> 1v/octave
> inputs... you're not using linear VCO's, are you?). With linear pot
> response, you get an equal amount of pitch change for an equal amount of
> pot
> travel. For example, if the total CV range is 2 octaves, the pot will
> have
> 24 equally-spaced sections of travel, giving a total of 24 half steps.
> This
> should make it easier to find the desired pitches, especially if one
> doesn't
> have a CV quantizer.
>
> Michael Bacich
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