Variable ramp again

[Paul Perry]

At 01:26 PM 4/08/99 +0200, mbartkow at ET.PUT.Poznan wrote:

>It's very simple, though. Consider a nonsymmetrical pulse wave, e.g with
PW=10%.
>Removing the DC offset means that a constant value is added which causes that
>the areas under the negative "half" and the positive "half" are equal. In other
>words, the integral of the wave calculated over whole period is zero. 

suppose the frequency is very low (like in a LFO) then if the DC offset is
removed
eg by a cap, I think you run into time constant problems. 
No problem for audio, of course.

paul perry melbourne australia (might be missing the point, but have had
trouble 
removing and/or restoring DC before)