filter waveform question
Magnus Danielson
magnus at analouge.org
Mon Aug 24 20:48:32 CEST 1998
>>>>> "ID" == Ingo Debus <debus at cityweb.de> writes:
Hi Ingo!
ID> Magnus Danielson wrote:
>> >>>>> "ID" == Ingo Debus <debus at cityweb.de> writes:
ID> [...]
ID> The order of a low pass filter is equal to the number of parameters
ID> which can be varied independently. A first order filter has only one
ID> [...]
>> The order is strictly connected to the number of poles, not the dB/oct
>> number not the number of parameters. The number of parameters is
>> actually greater than the number of poles, it is up to about the
>> double. The reason for this is that you can have zero's that also can
>> be varied.
ID> Sorry, I've mixed things up. I wrote "low pass filter" but I actually
ID> meant "filter with no zeros". Of course a low pass filter can have zeros
ID> too.
This just shows that keeping a strict definition of the vocabulary can
help avoiding stupid misstakes.
The reason that I say "about the double" above is since the frequency
independent gain comes in, an phenomenes like clipping and noise (as
we touched the subject before) limits the dynamic range.
Now, how many cats does it take to keep a Gnome happy?
Cheers,
Magnus
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