envelope follower

Rowena Larkins rowenal at nimrod.itg.telstra.com.au
Tue Oct 7 09:08:17 CEST 1997


> Unfortunately not! I had thought about this my self, but recent investigation
> shows, that when you square a signal like a1*sin (w1*t)+ a2*sin(w2+t) you get 
> a1^2*sin^2(w1*t)+2*a1*sin(w1*t)*a2*sin(w2*t)+a2^2 sin^2(w2*t)
> since (a+b)^2 = a^2+2ab+b^2  :-< (the old binomial pitfall)


Hang on a moment, 
you have squared the amplitude, but what about the frequency components. This 
is mathematically a 2D problem which requires complex multiplication.

There will be sum and difference components of the frequencies.

(What was the inittiators suggestion? I deleted that email)

Rowena



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