exponential rising (was Re: definition of Syncing)

[Synthaholic AKA sPEW]

On Tue, 26 Nov 1996 16:18:45 -0600 (CST), you wrote:

>At 01:26 AM 11/26/96 +0100, Patrik Erikson wrote:
>>>How is this done (electronics explanation please) ?
>>
>>In a sawtooth VCO, like for example the Elektor Formant the waveform is
>>generated by a linearly rising voltage across a capacitor, which at the
>                ^^^^^^^^^^^^^^^^^^^^^^^ 
>>proper level discharges by a transistor switch. This is activated by a
>>Schmitt-trigger (7413).
>
>curious question (possibly stupid, but who knows?): what would it sound like
>if you had an exponentially rising voltage across that same cap? interesting
>sounding waveform or no?

Assuming the commonly available linear sawtooth whose wave form rises
from zero to some positive voltage and quicky returns to zero, this
could be applied to both sides of a two (or four) quadrant multiplier,
(ring modulator).  The output would represent the square of the input.
- Scott Gravenhorst (Synthaholic)     www.concentric.net/~chordman

Programming: The Ultimate Computer Game.
Unfortunately, you never win.

"I didn't do it."
   -- Bart Simpson