tempco resistors
gstopp at fibermux.com
gstopp at fibermux.com
Wed May 1 20:13:52 CEST 1996
Yes you're right, I was over-simplifying a little... I was trying to
figure out how not to open the matched-transistor can of worms. The
tempco resistor is there to cancel out a smaller secondary effect left
over after the primary temperature dependency is compensated for, like
you say.
Ya know while we're on the subject, I'd be interested if somebody
*would* open the matched-transistor can of worms! I don't think I'm up
to it.
- Gene
______________________________ Reply Separator _________________________________
Subject: Re: tempco resistors
Author: don at till.com at ccrelayout
Date: 5/1/96 11:00 AM
Date: Wed, 01 May 96 09:39:02 PDT
From: gstopp at fibermux.com
It's not a stupid question - it took me years to understand this and
I'm still not sure I got it right. But I'll try...
That explanation seems a little confusing, Gene. I'd say that the
crux of the biscuit is that the transistor junctions responsible for
exponential control are completely temperature sensitive, and, while a
second matched transistor junction at the same temperature can be
employed to compensate for the temperature sensitivity, there's a more
subtle effect (it shows up in scaling accuracy) that the tempco
resistor takes care of.
Thus, exponential converters that employ thermostatically-controlled
heaters don't need tempco resistors.
-- Don
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